Review: Integration

To ensure success in this course, your integration skills must be flawless. Practice with the following exercises, and discuss among yourselves the best techniques to evaluate the integrals below. Feel free to drop questions and comments, and I will try to guide you in the right direction—without offering the solution, of course; that will spoil the fun for others that want to try by themselves.

  1. \displaystyle{\int_0^3 \frac{dx}{x-1} }
  2. \displaystyle{\int_{-\infty}^0 xe^{-x}\, dx }
  3. \displaystyle{\int \cos x \big( 1+\sin^2 x \big)\, dx }
  4. \displaystyle{\int \frac{\sin x + \sec x}{\tan x}\, dx }
  5. \displaystyle{\int_1^3 r^4 \ln r\, dr }
  6. \displaystyle{\int \frac{x-1}{x^2-4x+5}\, dx }
  7. \displaystyle{\int \sin^3 \theta \cos^5 \theta\, d\theta }
  8. \displaystyle{\int x\, \sin^2 x\, dx }
  9. \displaystyle{\int e^{x+e^x}\, dx }
  10. \displaystyle{\int e^2\, dx }
  11. \displaystyle{\int \frac{\ln x}{x \sqrt{1+ \big(\ln x \big)^2}}\, dx }
  12. \displaystyle{\int \big( 1+ \sqrt{x} \big)^8\, dx }
  1. \displaystyle{\int \ln \big( x^2-1 \big)\, dx }
  2. \displaystyle{\int \frac{3x^2-2}{x^2-2x-8}\, dx }
  3. \displaystyle{\int \frac{dx}{1+e^x} }
  4. \displaystyle{\int \sqrt{3-2x-x^2}\, dx }
  5. \displaystyle{\int \frac{1+\cot x}{4-\cot x}\, dx }
  6. \displaystyle{\int \sin 4x \cos 3x\, dx }
  7. \displaystyle{\int e^x \sqrt{1+e^x}\, dx }
  8. \displaystyle{\int \sqrt{1+e^x}\, dx }
  9. \displaystyle{\int x^5 e^{-x^3}\, dx }
  10. \displaystyle{\int \frac{1+\sin x}{1-\sin x}\, dx }
  11. \displaystyle{\int \frac{dx}{3-5\sin x} }
  12. \displaystyle{\int \frac{dx}{3\sin x - 4\cos x} }
  1. Bobby Frankenberger
    October 31, 2011 at 10:31 am

    For number two I changed the negative infinity to the variable t and then took the limit as t approaches negative infinity of the integral. I got an answer of infinity, but wolfram alpha states that the “integral does not converge”. Did I get the right answer then? When I calculate the limit as infinity does that mean that the integral does not converge?

  2. Eric Lambert
    January 26, 2012 at 2:18 pm

    Are there supposed to be two dx’s in number one?

  3. Caleb Padgett
    March 11, 2013 at 9:49 pm

    For # 1, does the integral simply not converge or is there a definite answer?

  1. No trackbacks yet.

Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out / Change )

Twitter picture

You are commenting using your Twitter account. Log Out / Change )

Facebook photo

You are commenting using your Facebook account. Log Out / Change )

Google+ photo

You are commenting using your Google+ account. Log Out / Change )

Connecting to %s

%d bloggers like this: